Detailed Description
The QStackedLayout class provides a stack of widgets where only one widget is visible at a time.
QStackedLayout can be used to create a user interface similar to the one provided by QTabWidget. There is also a convenience QStackedWidget class built on top of QStackedLayout.
A QStackedLayout can be populated with a number of child widgets ("pages"). For example:
QWidget *firstPageWidget = new QWidget;
QWidget *secondPageWidget = new QWidget;
QWidget *thirdPageWidget = new QWidget;
QStackedLayout *stackedLayout = new QStackedLayout;
stackedLayout->addWidget(firstPageWidget);
stackedLayout->addWidget(secondPageWidget);
stackedLayout->addWidget(thirdPageWidget);
QVBoxLayout *mainLayout = new QVBoxLayout;
mainLayout->addLayout(stackedLayout);
setLayout(mainLayout);
QStackedLayout provides no intrinsic means for the user to switch page. This is typically done through a QComboBox or a QListWidget that stores the titles of the QStackedLayout's pages. For example:
QComboBox *pageComboBox = new QComboBox;
pageComboBox->addItem(tr("Page 1"));
pageComboBox->addItem(tr("Page 2"));
pageComboBox->addItem(tr("Page 3"));
connect(pageComboBox, SIGNAL(activated(int)),
stackedLayout, SLOT(setCurrentIndex(int)));
When populating a layout, the widgets are added to an internal list. The indexOf() function returns the index of a widget in that list. The widgets can either be added to the end of the list using the addWidget() function, or inserted at a given index using the insertWidget() function. The removeWidget() function removes the widget at the given index from the layout. The number of widgets contained in the layout, can be obtained using the count() function.
The widget() function returns the widget at a given index position. The index of the widget that is shown on screen is given by currentIndex() and can be changed using setCurrentIndex(). In a similar manner, the currently shown widget can be retrieved using the currentWidget() function, and altered using the setCurrentWidget() function.
Whenever the current widget in the layout changes or a widget is removed from the layout, the currentChanged() and widgetRemoved() signals are emitted respectively.
See also QStackedWidget and QTabWidget.
Property Documentation
count : const int
This property holds the number of widgets contained in the layout.
Access functions:
- virtual int count () const
See also currentIndex() and widget().
currentIndex : int
This property holds the index position of the widget that is visible.
The current index is -1 if there is no current widget.
Access functions:
- int currentIndex () const
- void setCurrentIndex ( int index )
See also currentWidget() and indexOf().
Member Function Documentation
QStackedLayout::QStackedLayout ()
Constructs a QStackedLayout with no parent.
This QStackedLayout must be installed on a widget later on to become effective.
See also addWidget() and insertWidget().
QStackedLayout::QStackedLayout ( QWidget * parent )
Constructs a new QStackedLayout with the given parent.
This layout will install itself on the parent widget and manage the geometry of its children.
QStackedLayout::QStackedLayout ( QLayout * parentLayout )
Constructs a new QStackedLayout and inserts it into the given parentLayout.
QStackedLayout::~QStackedLayout ()
Destroys this QStackedLayout. Note that the layout's widgets are not destroyed.
int QStackedLayout::addWidget ( QWidget * widget )
Adds the given widget to the end of this layout and returns the index position of the widget.
If the QStackedLayout is empty before this function is called, the given widget becomes the current widget.
See also insertWidget(), removeWidget(), and setCurrentWidget().
void QStackedLayout::currentChanged ( int index ) [signal]
This signal is emitted whenever the current widget in the layout changes. The index specifies the index of the new current widget.
See also currentWidget() and setCurrentWidget().
QWidget * QStackedLayout::currentWidget () const
Returns the current widget, or 0 if there are no widgets in this layout.
See also currentIndex() and setCurrentWidget().
int QStackedLayout::insertWidget ( int index, QWidget * widget )
Inserts the given widget at the given index in this QStackedLayout. If index is out of range, the widget is appended (in which case it is the actual index of the widget that is returned).
If the QStackedLayout is empty before this function is called, the given widget becomes the current widget.
Inserting a new widget at an index less than or equal to the current index will increment the current index, but keep the current widget.
See also addWidget(), removeWidget(), and setCurrentWidget().
void QStackedLayout::setCurrentWidget ( QWidget * widget ) [slot]
Sets the current widget to be the specified widget. The new current widget must already be contained in this stacked layout.
See also setCurrentIndex() and currentWidget().
QWidget * QStackedLayout::widget ( int index ) const
Returns the widget at the given index, or 0 if there is no widget at the given position.
See also currentWidget() and indexOf().
void QStackedLayout::widgetRemoved ( int index ) [signal]
This signal is emitted whenever a widget is removed from the layout. The widget's index is passed as parameter.
See also removeWidget().
